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3x^2-84x+540=0
a = 3; b = -84; c = +540;
Δ = b2-4ac
Δ = -842-4·3·540
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-24}{2*3}=\frac{60}{6} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+24}{2*3}=\frac{108}{6} =18 $
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